An air bubble of radius 4.5 cm initially at a depth of 12 m below the water surface rises to the sur

The temperature is constant, so Boyle’s law applies: P₁V₁ = P₂V₂. Pressures in metres of water: at 12 m depth, P₁ = 10.34 + 12 = 22.34; at the surface, P₂ = 10.34.

V₂/V₁ = 22.34/10.34 = 2.16. Volume depends on r³, so r₂ = 4.5 × (2.16)^(1/3) = 4.5 × 1.293 = 5.82 cm.