A 120 V a.c. voltage source is connected across a pure 25.0 mH inductor. Find the current through th
Source: JAMB · 2023
A 120 V a.c. voltage source is connected across a pure 25.0 mH inductor. Find the current through the inductor if the frequency of the source is 120/π Hz.
Explanation
A pure inductor opposes a.c. with inductive reactance X_L = 2πfL.
X_L = 2π × (120/π) × 0.025 = 240 × 0.025 = 6 Ω.
Current I = V/X_L = 120/6 = 20 A. Remember to convert 25.0 mH to 0.025 H.
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