If the volume of an ideal gas is halved while its temperature is doubled, the pressure will

Source: JAMB · 2024

If the volume of an ideal gas is halved while its temperature is doubled, the pressure will

  1. decrease by a factor of 2
  2. increase by a factor of 2
  3. decrease by a factor of 4
  4. increase by a factor of 4 ✓
Explanation

For an ideal gas, PV/T stays constant. So P₂ = P₁ × (V₁/V₂) × (T₂/T₁).

Halving the volume gives V₁/V₂ = 2. Doubling the temperature gives T₂/T₁ = 2. So P₂ = P₁ × 2 × 2 = 4P₁. The pressure increases by a factor of 4.

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