A solid of density 1.25 x 10⁴ kgm⁻³ weighs 25 N in air. It is completely immersed in water of densit

Question

A solid of density 1.25 x 10⁴ kgm⁻³ weighs 25 N in air. It is completely immersed in water of density 1.00 x 10³ kgm⁻³. Calculate the apparent weight of the solid in water.

[g = 10 ms⁻²]

Answer 1

A solid of density 1.25 x 10⁴ kgm⁻³ weighs 25 N in air. It is completely immersed in water of density 1.00 x 10³ kgm⁻³. Calculate the apparent weight of the solid in water.

[g = 10 ms⁻²]

21 N
23 N ✓
24 N
20 N

Explanation

Mass of solid = 25 ÷ 10 = 2.5 kg. Volume = 2.5 ÷ 12,500 = 2 × 10⁻⁴ m³.

Upthrust = ρVg = 1000 × 2 × 10⁻⁴ × 10 = 2 N.

Apparent weight = 25 − 2 = 23 N.

Was this explanation helpful?

Something wrong or missing? Tell us — we read every report and fix issues fast.