A point charge q = +1.0 μC is moving with a velocity v = 5.0 × 10⁵ ms⁻¹ in a region of uniform magne

Question

A point charge q = +1.0 μC is moving with a velocity v = 5.0 × 10⁵ ms⁻¹ in a region of uniform magnetic field B = 0.020 T. The direction of the velocity is at an angle of 30° with the direction of the magnetic field. What is the magnitude of the magnetic force on the charge?

Answer 1

A point charge q = +1.0 μC is moving with a velocity v = 5.0 × 10⁵ ms⁻¹ in a region of uniform magnetic field B = 0.020 T. The direction of the velocity is at an angle of 30° with the direction of the magnetic field. What is the magnitude of the magnetic force on the charge?

4.0 × 10⁻³ N
5.0 × 10⁻³ N ✓
2.0 × 10⁻³ N
3.0 × 10⁻³ N

Explanation

The magnetic force on a moving charge is F = qvB sin θ.

F = (1.0 × 10⁻⁶) × (5.0 × 10⁵) × 0.020 × sin 30°.

sin 30° = 0.5, so F = 0.01 × 0.5 = 5.0 × 10⁻³ N.

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