The de Broglie wavelength of an electron with a mass of 9.11 x 10⁻³¹ kg and a velocity of 10⁶ ms⁻¹ i

JAMB Physics 2023 407 views
Source: JAMB · 2023

The de Broglie wavelength of an electron with a mass of 9.11 x 10⁻³¹ kg and a velocity of 10⁶ ms⁻¹ is

[h = 6.63 x 10⁻³⁴ Js]

  1. 6.04 x 10⁻⁸ m
  2. 6.04 x 10⁻¹⁰ m
  3. 7.28 x 10⁻⁸ m
  4. 7.28 x 10⁻¹⁰ m ✓
Explanation

de Broglie wavelength: λ = h ÷ (mv).

mv = 9.11 × 10⁻³¹ × 10⁶ = 9.11 × 10⁻²⁵ kg m s⁻¹.

λ = 6.63 × 10⁻³⁴ ÷ 9.11 × 10⁻²⁵ ≈ 7.28 × 10⁻¹⁰ m.

Was this explanation helpful?

Something wrong or missing? Tell us — we read every report and fix issues fast.

pastQuestions.ng pastquestions.ng