A 10,000 kg railroad car, A, traveling at a speed of 24.0 ms⁻¹ strikes an identical car, B, at rest. If the cars lock together as a result of the…
Source: JAMB · 2024
A 10,000 kg railroad car, A, traveling at a speed of 24.0 ms⁻¹ strikes an identical car, B, at rest. If the cars lock together as a result of the collision, what is their common speed just afterward?
Explanation
The cars lock together, so this is a perfectly inelastic collision. Momentum is conserved, but kinetic energy is not.
Momentum before = 10,000 × 24.0 + 10,000 × 0 = 240,000 kg m/s.
After the collision both cars (20,000 kg) move together: 20,000 × v = 240,000.
v = 12.0 ms⁻¹. The mass doubles, so the speed halves.
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