A piece of ice of mass 100 g and at temperature 0°C is put in 200 g of water at 25°C. How much ice will melt as the temperature of the water reaches…
Source: JAMB · 2024
A piece of ice of mass 100 g and at temperature 0°C is put in 200 g of water at 25°C. How much ice will melt as the temperature of the water reaches 0°C?
[The specific heat capacity of water = 4200 J kg⁻¹K⁻¹, Specific latent heat of fusion of ice = 3.4 × 10⁵ Jkg⁻¹]
Explanation
The water cools from 25°C to 0°C and gives heat to the ice. This heat melts some of the ice at 0°C.
Heat lost by water = mcΔθ = 0.2 kg × 4200 × 25 = 21 000 J.
Heat to melt mass m of ice = m × L = m × 3.4 × 10⁵.
So m = 21 000 ÷ 340 000 ≈ 0.062 kg = 62 g. This is less than 100 g, so some ice is left.
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