A man swung an object of mass 2 kg in a circular path with a rope 1.2 m long. If the object was swun

Question

A man swung an object of mass 2 kg in a circular path with a rope 1.2 m long. If the object was swung at 120 rev/min, find the tension in the rope.

Answer 1

A man swung an object of mass 2 kg in a circular path with a rope 1.2 m long. If the object was swung at 120 rev/min, find the tension in the rope.

Explanation

The tension in the rope gives the centripetal force: T = mω²r.

120 rev/min = 2 rev/s, so ω = 2π × 2 = 4π rad/s.

T = 2 × (4π)² × 1.2 = 2 × 157.9 × 1.2 ≈ 379 N.

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