An inductor with an inductance of 2 H and negligible resistance is connected to a 12 V, 50 Hz AC mains supply. Calculate the current flowing through…
Source: JAMB · 2024
An inductor with an inductance of 2 H and negligible resistance is connected to a 12 V, 50 Hz AC mains supply. Calculate the current flowing through the inductor.
Explanation
An inductor resists AC through its reactance: X_L = 2πfL.
X_L = 2 × 3.142 × 50 × 2 ≈ 628 Ω.
Current I = V ÷ X_L = 12 ÷ 628 ≈ 0.0191 A = 19 mA.
Was this explanation helpful?
Something wrong or missing? Tell us — we read every report and fix issues fast.