A 35 kΩ is connected in series with a resistance of 40 kΩ. What resistance R must be connected in pa

JAMB Physics 2023 198 views
Source: JAMB · 2023

A 35 kΩ is connected in series with a resistance of 40 kΩ. What resistance R must be connected in parallel with the combination so that the equivalent resistance is equal to 25 kΩ?

  1. 40 kΩ
  2. 37.5 kΩ ✓
  3. 45.5 kΩ
  4. 30 kΩ
Explanation

The series combination is 35 + 40 = 75 kΩ.

Put R in parallel with it: (75 × R) ÷ (75 + R) = 25.

75R = 1875 + 25R, so 50R = 1875 and R = 37.5 kΩ.

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