One mole of propane is mixed with five moles of oxygen. The mixture is ignited and the propane burns completely. What is the volume of the products…
Source: JAMB · 2024
One mole of propane is mixed with five moles of oxygen. The mixture is ignited and the propane burns completely. What is the volume of the products at s.t.p?
(G.M.V = 22.4 dm³ mol⁻¹)
Explanation
Propane burns completely: C₃H₈ + 5O₂ → 3CO₂ + 4H₂O.
One mole of propane and five moles of oxygen are exactly the amounts needed, so nothing is left over.
At s.t.p. the water is a liquid, so only carbon (IV) oxide counts as gas: 3 mol × 22.4 dm³ = 67.2 dm³.
Counting the water as gas would give 7 mol (156.8 dm³), which is not an option and is wrong at s.t.p.
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