The number of atoms of chlorine present in 5.85g of NaCl is [Avogadro’s Number = 6.02 x 10²³]

JAMB Chemistry 2024 232 views
Source: JAMB · 2024

The number of atoms of chlorine present in 5.85g of NaCl is [Avogadro’s Number = 6.02 x 10²³]

  1. 6.02 x 10²² ✓
  2. 5.85 x 10²³
  3. 6.02 x 10²³
  4. 5.85 x 10²⁴
Explanation

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol.

Moles of NaCl = 5.85 ÷ 58.5 = 0.1 mol.

Each NaCl unit has one chlorine atom, so 0.1 mol of chlorine atoms. Number of atoms = 0.1 × 6.02 × 10²³ = 6.02 × 10²².

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