The work function of a metal is 2.1 eV. What is the wavelength of light that will just cause the pho
The work function of a metal is 2.1 eV. What is the wavelength of light that will just cause the photoelectric effect in this metal?
[h = 6.63 x 10⁻³⁴ Js; 1 ev = 1.6 x 10⁻¹⁹ J]
Explanation
Step 1: Identify given values and what to find
Given: W = 2.1 eV, h = 6.63 × 10⁻³⁴ Js, c = 3 × 10⁸ ms⁻¹
Find: Threshold wavelength λ₀
Step 2: Convert work function to joules
W = 2.1 × 1.6 × 10⁻¹⁹ = 3.36 × 10⁻¹⁹ J
Step 3: At threshold, photon energy equals work function
Formula: E = hc/λ₀ = W
Therefore: λ₀ = hc/W
Step 4: Substitute and calculate
λ₀ = (6.63 × 10⁻³⁴ × 3 × 10⁸)/(3.36 × 10⁻¹⁹)
λ₀ = (1.989 × 10⁻²⁵)/(3.36 × 10⁻¹⁹)
λ₀ = 5.92 × 10⁻⁷ m = 592 nm
Step 5: The answer is 592 nm