If gas A has a molar mass of 2 g/mol and gas B has a molar mass of 32 g/mol, what is the ratio of th

JAMB Chemistry 2023 63 views

If gas A has a molar mass of 2 g/mol and gas B has a molar mass of 32 g/mol, what is the ratio of their diffusion rates?

  1. 1:1
  2. 1:2
  3. 4:1 ✓
  4. 4:4

Explanation

Step 1: State Graham’s Law
Graham’s Law: Rate₁/Rate₂ = √(M₂/M₁)
Lighter gases diffuse faster than heavier gases

Step 2: Identify the given values
Molar mass of gas A (M_A) = 2 g/mol
Molar mass of gas B (M_B) = 32 g/mol

Step 3: Apply Graham’s Law
Rate_A / Rate_B = √(M_B / M_A)
= √(32 / 2)
= √16
= 4

Step 4: Express as a ratio
Rate_A : Rate_B = 4 : 1

Conclusion: Gas A diffuses 4 times faster than gas B because it is 16 times lighter. The lighter the gas, the faster it moves and diffuses.

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