Copper(II) tetraoxosulphate(VI) (CuSO₄) is prepared by the action of dilute H₂SO₄ on black copper(II

Question

Copper(II) tetraoxosulphate(VI) (CuSO₄) is prepared by the action of dilute H₂SO₄ on black copper(II) oxide (CuO). The oxide dissolves in the acid to give a

Answer 1

Copper(II) tetraoxosulphate(VI) (CuSO₄) is prepared by the action of dilute H₂SO₄ on black copper(II) oxide (CuO). The oxide dissolves in the acid to give a

blue solution ✓
red solution
white solution
pink solution

Explanation

When copper oxide reacts with sulfuric acid, it forms copper sulfate dissolved in water. Copper ions in solution appear blue because they absorb red and orange light.

The chemical reaction is: CuO + H₂SO₄ → CuSO₄ + H₂O. The black copper oxide dissolves completely to form a clear blue liquid.

Most copper compounds in solution display this characteristic blue color. The color comes from copper ions surrounded by water molecules, which is why copper sulfate solutions are always blue.