A compound is found to contain 40% carbon, 6.7% hydrogen, and 53.3% oxygen by mass. What is the empi
A compound is found to contain 40% carbon, 6.7% hydrogen, and 53.3% oxygen by mass. What is the empirical formula of the compound?
Explanation
Step 1: Convert percentages to grams (assume 100g sample)
Carbon (C) = 40 g
Hydrogen (H) = 6.7 g
Oxygen (O) = 53.3 g
Step 2: Convert grams to moles using atomic masses
Moles of C = 40 ÷ 12 = 3.33 moles
Moles of H = 6.7 ÷ 1 = 6.7 moles
Moles of O = 53.3 ÷ 16 = 3.33 moles
Step 3: Divide by the smallest number of moles
Smallest = 3.33
C: 3.33 ÷ 3.33 = 1
H: 6.7 ÷ 3.33 = 2
O: 3.33 ÷ 3.33 = 1
Step 4: Write the empirical formula
The ratio is C:H:O = 1:2:1
Empirical formula = CH₂O
Remember: The empirical formula shows the simplest whole-number ratio of atoms. C₂H₄O₂ and C₆H₁₂O₆ are molecular formulas that are multiples of CH₂O.